Divide: 2y^5 + 10y^4 + 6y^3 + y^2 + 5y + 3 by 2y^3 + 1

Question 1

Divide:

2y5 + 10y4 + 6y3 + y2 + 5y + 3 by 2y3 + 1

Question 2

We have,

(2y5 + 10y4 + 6y3 + y2 + 5y + 3) / (2y3 + 1)

By using long division method

∴ (2y5 + 10y4 + 6y3 + y2 + 5y + 3) / (2y3 + 1) = y2 + 5y + 3

kratos · Answer 1 · 2021-02-08T14:14:25+0000

We have,

(2y5 + 10y4 + 6y3 + y2 + 5y + 3) / (2y3 + 1)

By using long division method

∴ (2y5 + 10y4 + 6y3 + y2 + 5y + 3) / (2y3 + 1) = y2 + 5y + 3

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