+1 vote
by kratos

Using division of polynomials state whether 2y – 5 is a factor of 4y4 – 10y3 – 10y2 + 30y – 15.

1 Answer

+1 vote
by kratos
 
Best answer

2y – 5 is a factor of 4y4 – 10y3 – 10y2 + 30y – 15

Firstly let us perform long division method

Since the remainder is 5y3 – 45y2/2 + 30y – 15, 2y – 5 is not a factor of 4y4 – 10y3 – 10y2 + 30y – 15.

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