Let number of machines be ‘x’ machines
When cost of one machine decreases = 200 – 50 = 150Rs
| Cost (Rs) | 200 | 150 |
| No. of machines | 75 | x |
We know k = xy
200 × 75 = 150 × x
x = (200×75)/150
= 100
∴ Raghu can buy 100 machines when he gets a discount of Rs 50 on each machine.