Constructing a triangle PQR in which QR = 6 cm, ∠Q = 60° and PR – PQ = 2 cm.
Steps of Construction :
Draw a line segment QR = 6 cm.
With the help of protractor draw a line segment Qx and ∠Q = 60°.
Produce line segment xQ upto y. mark T such that QT = 2 cm. Join TR.
If perpendicular bisector of TR is drawn, that meets line segment Qx at P. PR is joined.
Now, ∆PQR is constructed.