Data : Parallelogram ABCD and rectangle ABEF are on the same base AB and have equal areas.
To Prove: Perimeter of the parallelogram is greater than that of the rectangle.
Proof: 
ABCD and rectangle ABEF are on same base AB and in between AB || FC.
AB = CD (Opposite sides of )
AB = EF (Opposite side of rectangle)
∴ CD = EF
∴ AB + CD = AB + EF …………. (i)
Perpendicular drawn from the vertex to base is only smaller than remaining lines.
∴ FA < AD and BE < BC
∴ AF + BE < AD + BC ………. (ii)
Comparing (i) and (ii),
(AB + CD + AF + BE) < (AB + EF + AD + BC)
∴ Perimeter of the parallelogram is greater than that of the rectangle.
