Two charges 10μC and 5μC are at 1m apart. In order to make this distance 0.5 m, how much work would be done?

Question

Two charges 10μC and 5μC are at lm apart. In order to make this distance 0.5 m, how much work would be done?

Answer 1

q1 = 10μC = 10 × 10-6 C
q2 = 5μC = 5 × 10-6 C