How much energy is released in the following reaction?
7Li+p→α+α
Atomic mass of 7Li - 7.0160 u and that of 4He - 4.0026 u.
Li7 + p → l + α + E ; Li7 = 7.016u
α= 4He = 4.0026u ; p = 1.007276 u
E = Li7 + P – 2α = (7.016 + 1.007276)u – (2x 4.0026)u = 0.018076 u.
=>0.018076 x 931 = 16.828 = 16.83 MeV.
