Given details are,
Let edge length of three equal cubes = a
Then,
Sum of surface area of 3 cubes = 3 × 6a2 = 18a2
When these cubes are placed in a row adjacently they form a cuboid.
Length of new cuboid formed = a + a + a = 3a
Breadth of cuboid = a
Height of cuboid = a
Total surface area of cuboid = 2 (lb×bh×hl)
= 2 (3a×a + a×a + a×3a)
= 2 (3a2 + a2 + 3a2)
= 2 (7a2)
= 14 a2
Total surface area of new cuboid / sum of surface area of 3 cuboids = 14/18 = 7/9 = 7:9
∴ The ratio is 7:9