How much does a^2 − 3ab + 2b^2 exceed 2a^2 − 7ab + 9b^2?

Question 1

How much does a2− 3ab + 2b2exceed 2a2− 7ab + 9b2?

Question 2

By subtracting 2a2− 7ab + 9b2from a2− 3ab + 2b2we get the required expression

Required expression = (a2– 3ab + 2b2) – (2a2 – 7ab + 9b2)

= a2– 3ab + 2b2 – 2a2 + 7ab – 9b2

Collecting positive and negative like terms together, we get

= a2– 2a2 – 3ab + 7ab + 2b2 – 9b2

= – a2 + 4ab – 7b2

kratos · Answer 1 · 2020-04-16T11:05:35+0000

By subtracting 2a2− 7ab + 9b2from a2− 3ab + 2b2we get the required expression

Required expression = (a2– 3ab + 2b2) – (2a2 – 7ab + 9b2)

= a2– 3ab + 2b2 – 2a2 + 7ab – 9b2

Collecting positive and negative like terms together, we get

= a2– 2a2 – 3ab + 7ab + 2b2 – 9b2

= – a2 + 4ab – 7b2

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