+1 vote
in JEE by kratos

Consider the situation shown in figure (38-E13). The wire PQ has mass m, resistance r and can slide on the smooth, horizontal parallel rails separated by a distance l. The resistance of the rails is negligible. A uniform magnetic field B exists in the rectangular region and a resistance R connects the rails outside the field region. At t = 0, the wire PQ is pushed towards right with a speed v0. Find (a) the current in the loop at an instant when the speed of the wire PQ is v, (b) the acceleration of the wire at this instant, (c) the velocity v as a function of x and (d) the maximum distance the wire will move.

1 Answer

+4 votes
by kratos
 
Best answer

(a) When the speed is V

Emf = Bℓv

Resistance = r + r

Current = Blv/r + R

(b) Force acting on the wire = iℓB

(c) v = v0 + at = v0 - B2l2v/m(R + r)t [force is opposite to velocity]

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