Calculate binding energy for ({ 26 }^{ 56 }{ Fe }) nucleus [Given : mass of ({ 26 }^{ 56 }{ Fe }) = 55.9349 u, mass of neutron = 1.00867 u, mass of proton = 1.00783 u and 1 u = 931MeV/c2] .
Mas defect Δm = [(30mn + 2mp) – M (26Fe56)] Δm = (30 × 1.00867+ 26 × 1.00783)u – 55.9349u Δm = (30 × 2601 + 26.20358) u – 55.9349 u Δm = 56.46368 – 55.9349u Δm = 0.52878u EB = 0.52878 × 931 MeV EB = 492.29 MeV ≈ 492 MeV
