A hydrogen atom in state n = 6 makes two successive transitions arid reaches the ground state. In the first transition a photon of 1.13 eV is emitted, (a) Find the energy of the photon emitted in the second transition, (b) What is the value of n in the intermediate state ?
Energy at n = 6, E =-13.6/36= –0.3777777
Energy in groundstate = –13.6 eV
Energy emitted in Second transition = –13.6 –(0.37777 + 1.13)
= –12.09 = 12.1 eV
b) Energy in the intermediate state = 1.13 ev + 0.0377777
