+1 vote
in JEE by kratos

ABCD is quadrilateral. Is AB + BC + CD + DA < 2 (AC + BD) ?

1 Answer

+3 votes
by kratos
 
Best answer

In ∆ AOB OA + OB > AB — 1

( Sum of the length of any 2 sides of a triangle is greater than the 3rd side.)

In ∆ BOC

OB + OC > BC — 2 ( Sum of the length of any 2 sides of a triangle is greater than the 3rd side.)

In ∆ COD

OC + CD > CD — 3 ( Sum of the length of any 2 sides of a triangle is greater than the 3rd side.)

In ∆ AOD

OA + OD > AD — 4 ( Sum of the length of any 2 sides of a triangle is greater than the 3rd side.)

Add all the 4

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