The light emitted in the transition n = 3 to n = 2 in hydrogen is called Hα light. Find the maximum work function a metal can have so that Hα light can emit photoelectrons from it.
n1 = 2, n2 = 3
Energy possessed by Hα light
= 13.6 (1/n12 – 1/n22) = 13.6 x (1/4 – 1/9) = 1.89 eV.
For Hα light to be able to emit photoelectrons from a metal the work function must be greater than or equal to 1.89 ev.
