+3 votes
by kratos

Subtract :

(i) -5y2 from y2

(ii) 6xy from – 12xy

(iii) (a – b) from (a + b)

(iv) a(b – 5) from b(5 – a)

(v) -m2 + 5mn from 4m2 – 3mn + 8

(vi) -x2 + 10x – 5 from 5x – 10

(vii) 5a2 – 7 ab + 5b2 from 3ab – 2a2 – 2b2

(viii) 4pq – 5q2 – 3p2 from 5p2 + 3q2 – pq

1 Answer

+6 votes
by kratos
 
Best answer

(i) -5y2 from y2

= y2 – (-5y2)

= y2 + 5y2 = 6y2

(ii) 6xy from – 12xy

= -12xy – (6xy)

= -12xy – 6xy = -18xy

(iii) (a – b) from (a + b)

= a + b – (a – b)

= a + b - a + b

= 2b

(iv) a(b – 5) from b(5 – a)

= ab – 5a from 5b – ab

= (5b – ab) – (ab – 5a)

= 5b – ab – ab + 5a

= 5a – 5b – 2ab

(v) -m2 + 5mn from 4m2 – 3mn + 8

= (4m2 – 3mn + 8) – (-m2 + 5mn)

= 4m2 – 3mn + 8 + m2 – 5mn

= 4m2 + m2 – 3mn – 5mn + 8

= 5m2 – 8mn + 8

(vi) -x2 + 10x – 5 from 5x – 10

= (5x – 10) – (-x2 + 10x – 5)

= 5x – 10 + x2 – 10x + 5

= 5x – 10x + x2 – 10 + 5

= x2 – 5x – 5

(vii) 5a2 – 7 ab + 5b2 from 3ab – 2a2 – 2b2

= (3ab – 2a2 – 2b2) – (5a2 – 7ab + 5b2)

= 3ab – 2a2 – 2b2 – 5a2 + 7ab – 5b

= -2a2 – 5a2 – 2b2 – 5b2 + 7ab + 3ab

= -7a2 – 7b2 + 10ab

(viii) 4pq – 5q2 – 3p2 from 5p2 + 3q2 – pq

= (5p2 + 3q2 – pq) – (4pq – 5q2 – 3p2)

= 5p2 + 3q2 – pq2 – 4pq + 5q2 + 3p2

= 5p2 + 3p2 + 3q2 + 5q2 – 4pq – pq

= 8p2 + 8q2 – 5pq

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