Given numbers are 43, 91 and 183.
Subtract smallest number from both the highest numbers.
we have three cases:
183 > 43; 183 > 91 and 91 > 43
183 – 43 = 140
183 – 91 = 92 and
91 – 43 = 48
Now, we have three new numbers: 140, 48 and 92.
Find HCF of 140, 48 and 92 using prime factorization method, we get
HCF (140, 48 and 92) = 4
The highest number that divide 183, 91 and 43 and leave the same remainder is 4.
