In the Figure, the blocks are of equal mass. The pulley is fixed & massless. In the position shown, A is given a speed u and vB= the speed of B. (θ < 90°)
(A) B will never lose contact with the ground
(B) The downward acceleration of A is equal in magnitude to the horizontal acceleration of B.
(C) vB = ucosθ
(D) vB = u/cosθ
