Here 1600 years have ‘0’ odd day .......(A).
100years have ‘5’ odd days ..........(B)
75years = (18leap years + 57ordinary years)
= (18 × 2 + 57 × 1)
= 93odd days
= (7 × 13 + 2) = ‘2’ odd days ........(C)
Now, the no. of days from 1st January to 18 July, 1776
= 182 + 18 = 200days
= (28 × 7 + 4)days = ‘4’odd days ...... (D)
Adding (A) + (B) + (C) + (D),
We get, 0 + 5 + 2 + 4 = 04odd days
Ans. Thursday
