+2 votes
in JEE by kratos

A particle performs harmonic oscillations along the x-axis about the equilibrium position x = 0. The oscillation frequency is ω = 4.00s-1 At a certain moment of time the particle has a coordinate xo = 25.0cm and its velocity is equal to vx0 = 100cm/*.

Find the coordinate x and the velocity vs of the particle t = 2.40s after that moment.

1 Answer

+4 votes
by kratos
 
Best answer

Let the general equation of *.H.M. be

Let us assume that at t = 0, x = x0 and vx = vx0.

Under our assumption eqns (1) and (2) given the sought x and vx if

Putting all the given numerical values, we get:

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