Question

A cylinder rotating at an angular speed of 50 rev/* is

brought in contact with an identical stationary cylinder.

Because of the kinetic friction, torques act on the two

cylinders, accelerating the stationary one and

decelerating the moving one. If the common magnitude

of the acceleration and deceleration be one revolution

per second square, how long will it take before the two

cylinders have equal angular speed ?

Answer 1

A cylinder is moving with an angular velocity 50 rev/* brought in contact with another identical cylinder in rest. The first and second cylinder has common acceleration and deacceleration as 1 rad/s2 respectively.