Simplify the Boolean expression (A + B + C)(D + E)’ + (A + B + C)(D + E) and choose the best answer.
(a) A + B + C
(b) D + E
(c) A’B’C’
(d) D’E’
(e) of these
(A+B+C)(D+E)' + (A+B+C)(D+E)
= (A+B+C)((D+E)+(D+E)’) (Distributive Law)
= (A+B+C).(1) (X+X’=1)
= A+B+C
So, simplification of the Boolean expression (A + B + C)(D + E)’ + (A + B + C)(D + E) yields A+B+C