Simplification of the Boolean expression (A + B)’(C + D + E)’ + (A + B)’ yields which of the following results?
(a) A + B)
(b) A’B’
(c) C + D + E
(d) C’D’E’
(e) A’B’C’D’E
(A + B)'(C + D + E)' + (A + B)'=(A+B)’((C+D+E)+1) (Distb. Law)
=(A+B)’.1 (Identity Law)
=(A+B)’ (Identity Law)
=A’B’ (DeMorgan’* Law)
So, simplification of the Boolean expression (A + B)’(C + D + E)’ + (A + B)’ yields
