A capacitor of capacitance 10 μF is connected to an AC source and an AC Ammeter, if the source voltage varies as V = 50√2 sin 100 t, the reading of the ammeter is
(1) 70.7 mA
(2) 7.07 mA
(3) 50 mA
(4) 5.0 mA
Correct option (3) 50 mA
Explanation:
V = 50√2 sin100t
Comparing with V = V0 sin ωt
V0 = 50 2 V, ω= 100
= Ammeter reading
[**Note:** Ammeter reads rms value of current]
