If L1 = 0 is the reflected ray, then its equation is (A) (x + 10)/4 = (y - 5)/4 = (z + 2)/3

Question

A ray of light is coming along the line L = 0 and strikes the plane mirror kept along the plane P = 0 at B. A(2, 1, 6) is a point on the line L = 0 whose image about P = 0 is A′. It is given that L = 0 is (x - 2)/3 = (y - 1)/4 = (z - 6)/5 and P = 0 is x + y - 2z = 3.

If L1 = 0 is the reflected ray, then its equation is

(A) (x + 10)/4 = (y - 5)/4 = (z + 2)/3

(B) (x + 10)/3 = (y + 15)/5 = (z + 14)/5

(C) (x + 10)/4 = (y + 15)/5 = (z + 14)/3

(D) of these

Answer 1

Answer is (C) (x + 10)/4 = (y + 15)/5 = (z + 14)/3

Equation of reflected ray L1 = 0 is line joining Q(x2, y2, z2) and B(-10, -15, -14). That is,