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Recent questions tagged three-dimensional geometry
+2
votes
1
answer
The equation vector |r|^2 - r(2i + 4j - 2k) - 10 = 0 represents a (A) Plane (B) Sphere of radius 4
asked
Apr 5, 2019
in
JEE
by
kratos
jee
three-dimensional geometry
jee mains
+3
votes
1
answer
Find the shortest distance between the lines : vector r=(i+2j+3k)+λ(i-3j+2k) and vector r=(4j+5k+6k)+μ(2i+3j+k)
asked
Mar 25, 2019
in
JEE
by
kratos
isc
cbse
three-dimensional geometry
jee
icse
jee mains
class-12
straight line in space
three dimensional geometry
+2
votes
1
answer
If A = (p, q, r) and B = (p′, q′ r′) are two points on the line λx = μy = γz, such that OA = 3, OB = 4,
asked
Mar 21, 2019
in
JEE
by
kratos
hyperbola
vector algebra
class-8
jee
class-6
jee mains
three-dimensional geometry
geometry
sets
+1
vote
1
answer
If the x-coordinate of a point P on the join of Q(2, 2, 1) and R(5, 1, -2) is 4, then find its z-coordinate.
asked
Mar 19, 2019
in
JEE
by
kratos
jee
three-dimensional geometry
jee mains
+2
votes
1
answer
The ratio in which the plane E = ax + by + cz + d = 0 divides the segment joining the points A(x1, y1, z1) and
asked
Mar 16, 2019
in
Class 12
by
kratos
class-12
three-dimensional geometry
three dimensional geometry
+3
votes
1
answer
Show that the points A = (-1, -3, 4), B = (-2, 1, -4) and C = (3, -11, 5) form an isosceles triangle.
asked
Mar 13, 2019
in
JEE
by
kratos
jee
class-11
three-dimensional geometry
jee mains
+2
votes
1
answer
If the line (x - x1)/l = (y - y1)/m = (z - z1)/n is parallel to the plane ax + by + cz + d = 0, then
asked
Mar 12, 2019
in
JEE
by
kratos
jee
jee mains
class-12
three-dimensional geometry
three dimensional geometry
+1
vote
1
answer
The area enclosed by the curves y = sinx + cosx and y = |cosx – sinx| over the interval [0, π/2] is
asked
Mar 8, 2019
in
JEE
by
kratos
area
jee
area under the curves
area bounded by the curves
jee mains
three-dimensional geometry
+2
votes
1
answer
If L1 = 0 is the reflected ray, then its equation is (A) (x + 10)/4 = (y - 5)/4 = (z + 2)/3
asked
Mar 5, 2019
in
JEE
by
kratos
jee
three-dimensional geometry
jee mains
+3
votes
1
answer
The equation of a straight line parallel to the x-axis is given by (A) (x - a)/1 = (y - b)/1 = (z - c)/1
asked
Feb 28, 2019
in
JEE
by
kratos
jee
three-dimensional geometry
jee mains
+2
votes
1
answer
The plane E ≡ ax + by + cz + d = 0 contains the line L : (x - x1)/l = (y - y1)/m = (z - z1)/n
asked
Feb 27, 2019
in
JEE
by
kratos
jee
jee mains
class-12
three-dimensional geometry
three dimensional geometry
+2
votes
1
answer
A plane is passed through the middle point of the segment A(-2, 5, 1) and B(6, 1, 5) and is perpendicular to this line. Its equation is
asked
Feb 26, 2019
in
JEE
by
kratos
jee
three-dimensional geometry
jee mains
+2
votes
1
answer
Two systems of forces P, Q, R and P′, Q′, R′ are along the side BC, CA, AB of a ∆ABC.
asked
Feb 24, 2019
in
JEE
by
kratos
hyperbola
vector algebra
class-8
jee
class-6
jee mains
three-dimensional geometry
geometry
sets
+3
votes
1
answer
Prove that the points A (1, 7), B (4, 2), C (−1, −1) and D (−4, 4) are the vertices of a square.
asked
Feb 16, 2019
in
JEE
by
kratos
class-11
jee
class-10
jee mains
coordinate geometry
three-dimensional geometry
three dimensional geometry
+3
votes
1
answer
Find the angle between the lines vector r = 4i - j + λ(i + 2j - 2k) and vector r = i - j + 2k - μ(2i + 4j - 4k)
asked
Feb 13, 2019
in
JEE
by
kratos
isc
jee
straight line in space
icse
jee mains
class-12
three-dimensional geometry
+1
vote
1
answer
Find the shortest distance between the lines vector r = (4i - j) + λ(i + 2j - 3k) and vector r = (i - j + 2k) + μ(2i + 4j - 5k).
asked
Feb 6, 2019
in
JEE
by
kratos
isc
cbse
jee
straight line in space
icse
jee mains
class-12
three-dimensional geometry
+1
vote
1
answer
Find out the perpendicular distance of point P(0, -1, 3) from a straight line passing through A(1, -3, 2)
asked
Feb 1, 2019
in
JEE
by
kratos
jee
three-dimensional geometry
jee mains
+1
vote
1
answer
In a triangle ABC, coordinates of A are (1, 2) and the equations of the medians through B and C are x + y = 5 and x = 4 respectively.
asked
Jan 27, 2019
in
JEE
by
kratos
jee
three-dimensional geometry
lines
jee mains
+3
votes
1
answer
The y-intercept of the line y + y1 = m(x – x1) is ….. (a) – (y1 + mx1) (b) y1 – mx1
asked
Jan 24, 2019
in
JEE
by
kratos
three-dimensional geometry
jee
jee mains
lines
+2
votes
1
answer
The vector PF is (A) 7j + 7k (B) 7/√2(j + k) (C) j + k
asked
Jan 22, 2019
in
JEE
by
kratos
three-dimensional geometry
jee
jee mains
vector algebra
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