∫1÷(1+cos2x)2dx
∫1÷(sin2x+cos2x+cos2x-sin2x)2dx
∫1÷(2cos2x)2dx
(1÷4)∫sec4x dx
(1÷4)∫sec2x(1+tan2x) dx
(1÷4)∫sec2x+sec2xtan2x dx
1/4[tanx+(tan3x÷3)]+C..Answer