1 Answer

+1 vote
by kratos
 
Best answer

∫1÷(1+cos2x)2dx

∫1÷(sin2x+cos2x+cos2x-sin2x)2dx

∫1÷(2cos2x)2dx

(1÷4)∫sec4x dx

(1÷4)∫sec2x(1+tan2x) dx

(1÷4)∫sec2x+sec2xtan2x dx

1/4[tanx+(tan3x÷3)]+C..Answer

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