+1 vote
in Class 12 by kratos

An n-p-n transistor in a common-emitter mode is used as a simple voltage-amplifier with a collector-current of 4mA. The terminals of a 8V battery is connected to the collector through a load-resistance RL and to the base through a resistance RB. The collector-emitter voltage VCE = 4 V, the baseemitter voltage VBE = 0.6 V and the current amplification factor βdc = 100. Then

(a) RL = 1 kΩ, RB = 185 kΩ

(b) RL = 2 kΩ = RB

(c) RL = 2 kΩ, RB = 15 kΩ

(d) RL = 185 kΩ, RB = 1 kΩ

1 Answer

+4 votes
by kratos
 
Best answer

Correct option (a)

Explanation:

An n-p-n transistor in a commonemitter mode with connections as given is shown in figure.

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