Question

A man’* age is three times that of his son, and in twelve years he will be twice as old as his son would be. What are their present ages.

Answer 1

Let present age of the son = x years

present age of the man = 3x years In 12 years :

Son’* age will be = (x + 12) years

The man’* age will be = (3x + 12) years

According to the statement :

3x + 12 = 2(x + 12)

=> 3x + 12 = 2x + 24

=> 3x – 2x = 24 – 12

=> x = 12

3x = 3 x 12 = 36

Hence, present age of the man = 36 years

Present age of the son = 12 years.