Magnitude of the force F2 for Equilibrium
The magnitude of force F2 may be found by equating the force acting towards right to those acting towards left,
Total elongation of the Member
For the sake of simplicity, the force of 36500 kg may be split up into two force of 4500 kg and 32000 kg. The force of 45000 kg acting at C may be split into two forces of 32000 kg and 13000 kg, Now, it will be seen that the part AB of the member is subjected to a tension of 4500 kg , part BC is subjected to a compression of 32000 kg and part CD is subjected to a tension of 13000 kg, Using the relation,
