Question

A light ray passes through substances 1, 2, and 3, as shown. The indices of refraction for these three substances are n1, n2, and n3, respectively. Ray segments in 1 and in 3 are parallel. From the directions of the ray, one can conclude that

(A) n3 must be the same as n1

(B) n2 must be less than n1

(C) n2 must be less than n3

(D) n1 must be equal to 1.00

(E) all three indices must be the same

Answer 1

The correct option is: (A) n3 must be the same as n1

Explanation:

If the angle in equals the angle out in a 3 tier medium arrangement, then the substances on the outsides must be the same.