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Let f(x) = (1 + b^2)x^2 + 2bx + 1 and let m(b) be the minimum value of f(x). As b varies, the range of m(b) is

+1 vote
in JEE by kratos

Let f(x) = (1 + b2)x2 + 2bx + 1 and let m(b) be the minimum value of f(x). As b varies, the range of m(b) is

(a) [0, 1]

(b) [0, 1/2]

(c) [1/2, 1]

(d) (0, 1]

1 Answer

+4 votes
by kratos
 
Best answer

The correct option (d) (0, 1]

Explanation:

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