The correct option (D) (2/9)R
Explanation:
it can be seen than three resistors each of value R are connected in parallel between points A, C and A, B and B,C.
Hence R equivalent between there points will be
{1/Req} = (1/R) + (1/R) + (1/R) = (3/R)
Req = (R/3)
Hence circuit can be drawn as
Hence RAB = (R/3) || {(R/3) + (R/3)}
= (R/3) || (2R/3)
= [{(R/3) × (2R/3)}/{(R/3) + (2R/3)}
= (2/9)R