+1 vote
in JEE by kratos

A particle moves along the X-axis as x = u(t – 2 )+ a(t – 2 ) 2.
(a) the initial velocity of the particle is u
(b) the accelerati?n of the particle is a
(c) the acceleration of the particle is 2a
(d) at t = 2 * particle is at the origin.

1 Answer

+5 votes
by kratos
 
Best answer

(c) the acceleration of the particle is 2a
(d) at t = 2s particle is at the origin.

Explanation:

The velocity at any instant is given by v=dx/dt=u+2a(t-2) initial velocity is the velocity at t=0, putting this value we get v=u-4a which is not zero.

So, (a) is incorrect. Acceleration is given by dv/dt =2a, So (b) is incorrect and (c) is correct. Putting t=2 * in the given displacement equation we get x=0, so (d) is also correct.

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