+2 votes
in JEE by kratos

A mass 2kg is suspended as shown in figure. The system is in equilibrium in vertical plane. Assume pulleys to be massless. The force constant of the spring is 100 N/m.If the extension in the spring is given by x/10 m. Find x? (g = 10 m/s2)

1 Answer

+1 vote
by kratos
 
Best answer

T = Mg

T1 = T + Mg = 2Mg

Kx = 2T1

or x = 2T1 /K = 4Mg/K

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