+1 vote
in Class 12 by kratos

The basic information, about a given ***** gauge, is as follows:

(i) Least division on the main scale = 0.5 mm

(ii) No. of divisions on the circular scale = 100

(iii) Distance moved, on the main scale, when the ***** is given 7 complete rotations = 3.5 mm

(iv) Circular scale division, coinciding with the line of graduated (reference) line, when the ‘jaws’, of the ***** gauge, are just in contact = 97

When a wire is just held in contact with the jaws of the ***** gauge, the main scale reads 0.45 mm. The circular scale division, just coinciding the reference line, is the 33rd division.

The zero error, and the corrected value of the radius of the wire, are equal, respectively, to

(1) + 0.0015 cm and 0.0308 cm

(2) – 0.0015 cm and 0.0315 cm

(3) – 0.0015 cm and 0.0308 cm

(4) + 0.0015 cm and 0.0030 cm

1 Answer

+5 votes
by kratos
 
Best answer

Correct option: (2) – 0.0015 cm and 0.0315 cm

Explanation:

Zero error = – (100–97) × L.C = – (.0015) cm

Observed total reading = (0.045 + 33 × 0.0005) cm

= 0.0615 cm

Corrected reading = [0.0615 – (-.0015)] cm

= 0.0630 cm

∴ Radius = 0.0315 cm

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