Question

Four capacitors are connected as shown in the adjoining fig. The potential difference between A and B is 1500 volt. The energy stored in 2 μF capacitor will be :

(a) 50.6 J

(b) 0.81 J

(c) 0.506 J

(d) none

Answer 1

Correct option (b) 0.81 J

Explanation:

Since, 2 μF and 3 μF capacitors are in parallel.

So, their effective capacitance is

C′ = 2 + 3 = 5 μF

Now 12 μF, 20 μF and C′ are in series.

Therefore, their effective capacitance is

The charge at C′, 20 μF and 12 μF capacitors is equal

Hence, potential difference across 2 μF capacitor

So, energy stored in 2 μF capacitor will be