Question

A 50 ohm lossless transmission line has a pure reactance of (j100) ohms as its load. The VSWR in the line is

(a) 1/2

(b)2

(c) 4

(d)(infinity)

Answer 1

Correct option (d)(infinity)

Explanation:

Reflection coefficient

Γ = (zL - z0)/(zL + z0) = (j100 - 50)/(j100 + 50)

Γ = √(1002 + 502)/√(1002 + 502) = 1

VSWR = (1 + |Γ|)/(1 - |Γ|) = (1 + 1)/(1 - 1) = 2/0 = ∞