For Equilibrium
∑H = 0; RAH = 15KN
∑V = 0; RAV + RBV = 0
∑MB = 0; RAV X 4 + 10 X 4 + 5 X 8 = 0
RAV = – 20 KN
And RBV = 20KN
Consider ***** A as shown in fig(a)
Consider ***** B as shown in fig (b)
∑H = 0;
– TAB – TBF cos 45 = 0
TBF = – 15/cos 45 = – 21.21KN
TBF = – 21.21KN(C)
∑V = 0
TBC + TBF sin 45 + 20 = 0
TBC – 21.21 sin 45 + 20 = 0
TBC = – 5KN(C)