The cubic unit cell of an oxide of metals A and B is as given below, in which oxygen. A and B are represented by open circles, crossed circles and dark circle respectively.
The formula of the oxide can be deduced as
(A) AB8O12
(B) ***
(C) ABO6
(D) ABO3
Correct answer is (D) ABO3
Number of atoms of A/unit cell = 1
Number of atoms of B/unit cell = 8 x 1/8 = 1
Number of atom of 0/unit cell = 12 x 1/4 =3
So, the formula of the oxide is ABO3.
