A carnot engine having an efficiency of 1/10 is being used as a refrigerator. If the work done on the refrigerator is 10 J, the amount of heat absorbed from the reservoir at lower temperature is :
(1) 99 J
(2) 100 J
(3) 90 J
(4) 1 J
Answer is (3) 90 J
Refrigerator cycle is :
Q = 90 J
Heat absorbed from the reservoir at lower temperature is 90 J
